If a and b are two consecutive integers such that a>b and product of the two integers is c. Then $(a + b)^{2}$ =

1-4c

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1+4c

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1-2c

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1+2c

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Solution

The correct option is B
1+4c

$(a + b)^{2}$ = $(a - b)^{2}$ + 4ab = 1 + 4c (since both are consecutive)

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