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Factors of a Number

If a and b ar...

Question

If a and b are two consecutive integers such that a>b and product of the two integers is c. Then (a+b) $^{2}$ =

1-4c

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1+4c

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1-2c

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1+2c

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None of these

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Solution

The correct option is B
1+4c

(a+b) $^{2}$ = (a-b) $^{2}$ + 4ab = 1 + 4c (since both are consecutive)

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Similar questions

If a and b are two consecutive integers such that a>b and product of the two integers is c. Then $(a + b)^{2}$ =

x^{2} - b x + c = 0

x^{2} - b x + c = 0

b^{2} - 4 c = 1

a, b, c

4 a b c x^{2} + (b^{2} - 4 a c) x - b = 0

x^{2} - b x + c = 0

b^{2} - 4 c = 1

a, b, c

4 a b c x^{2} + (b^{2} - 4 a c) x - b = 0

x^{2} - b x + c = 0

b^{2} - 4 c

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