If a,b>0 satisfy a3+b3=a-b, then
a2+b2>1
a2–b<0
a2+b2=1
a2+ab+b2<1
Explanation for the correct option:
Given, a3+b3=a–b
Let a=23,b=13
233+133=23–13
⇒ 827+127=13
⇒ 13=13
∴a2+ab+b2=49+23×13+19=49+29+19=79<1
Hence, Option ‘D’ is Correct.
If a+b+c=0 then (a3+b3+c3) is (a) 0 (b) abc (c) 2abc (d) 3abc