Question

If $a:b=3:8,$ find the value of $\frac{4a+3b}{6a-b}$

Answer 1

$a:b=3:8⟹\frac{a}{b}=\frac{3}{8}$

$\frac{4a+3b}{6a-b}=\frac{4(\frac{a}{b})+3}{6(\frac{a}{b})-1}=\frac{\frac{3}{2}+3}{\frac{9}{4}-1}=\frac{18}{5}$