If A-B-900 and cos B-3-5- then the value of sin A is -

The correct option is C 3/5 [ cosB = 3/5 since A + B = 90^0⇒B = 90 A; cos( 90 A) = 3/5⇒sinA = 3/5 ] ...

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If A+B=900 an...

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If A + B = 90 $^{0}$ and cos B = $\frac{3}{5}$ , then the value of sin A is -

4/5

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2/5

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3/5

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4/3

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2/3

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0 < A < 90^{0} : 0 < B < 90^{0}; sin A = \frac{12}{13}

cos B = \frac{4}{5}

sin (A + B)

sin (A + B)

sin A = \frac{3}{5}

c o s B = \frac{8}{17}

\frac{84}{85}

If cos B = $\frac{3}{5}$ and (A + B) = $90^{o}$ , find the value of sin A.

\frac{sin A}{sin B} = \frac{\sqrt{3}}{2}

\frac{cos A}{cos B} = \frac{\sqrt{5}}{2}, 0 < A, B < \frac{π}{2},

tan A + tan B

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