If (A+B)=90°, cosB=3/5,what is the value of SinA?

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Solution

A+B=90
⇒B=90-A

cos B=3/5
⇒cos (90-A)=3/5 [∵B=90-A]
⇒sin A=3/5 [∵cos(90-A)=sin A]

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