If a,b and c are non-zero and different from 1, then the value of loga1logablogacloga1blogb1loga1cloga1clogaclogc1 is
0
1+loga(a+b+c)
loga(a+b+c)
1
Explanation for the correct option:
Find the value of given determinant:
△=loga1logablogacloga1blogb1loga1cloga1clogaclogc1
⇒△=0logablogac-logab0-logac-logaclogac0
⇒△=0−logab0−(logac)2+logac−logablogac−0
⇒△=logab(logac)2−logab(logac)2
∴△=0
Hence, option ‘A’ is Correct.