1
Question
If a,b are any two odd positive integers such that a>b, then the largest positive integer which divides all the number of the form a2−b2 is
If a,b are any two odd positive integers such that a>b, then the largest positive integer which divides all the number of the form a2−b2 is
Open in App
Solution
The correct option is D 8
As a,b both are odd such that a>b
Let a=2n−1,b=2n−3 ∀ n ϵN.
Now p(n)=a2−b2=(a+b)(a−b)=8(n−1), which is divisible by 8.
Ans: C
As a,b both are odd such that a>b
Let a=2n−1,b=2n−3 ∀ n ϵN.
Now p(n)=a2−b2=(a+b)(a−b)=8(n−1), which is divisible by 8.
Ans: C
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
