In the given problem, we have to find value of
Given and
Squaring the equation, we get
(a+b+c)2=02
⇒a2+b2+c2+2ab+2bc+2ac
Now putting the value of in above equation we get,
Taking 2 as common factor we get
Hence the value of is .
If a2+b2+c2=16 and ab + bc + ca = 10, find the value of a + b + c.
If a+b+c=0 then find value of a2bc+b2ac+c2ab
If a2+b2+c2=20,a+b+c=0,find ab+bc+ca.