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Question

If A+B+C=180o and tan3A+tan3B+tan3C=k tan3A.tan3B.tan3C then k=

A
1
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B
3
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C
2
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D
4
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Solution

The correct option is A 1
A+B+C=180tan3A+tan3B+tan3C=Ktan3Atan3Btan3CA+B=180Ctan(3(A+B)=tan(3(180C))tan3A+tan3B1tan3A+tan3B=tan3Ctan3A+tan3B=tan3C+tan3Atan3Btan3Ctan3A+tan3B+tan3C=tan3Atan3Btan3C
k=1

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