If a,b,c are in A.P. and k is any non zero number, then ka,kb,kc are in......
The correct option is B (G.P).
Given a,b,c are in A.P, then their common difference for any consecutive terms is same.
So, b−a=c−a
Let ka,kb,kc are in G.P then their common ratio is same.
So, kbka=kckb
⇒kb−a=kc−b [Since, xmxn=xm−n]
⇒b−a=c−b which is true.
Hence, ka,kb,kc are in G.P