3
-3
0
1
R1→ R1+ R3-2R2 and using 2b-a-c=0
[∵ a, b, c are in AP]
We get the given determinant having all elements, in the first row as zero.
∴ The value of determinant = 0.
If 18,a,(b−3) are in AP, then find the value of (2a−b)