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Question

If a, b, c are in G.P., prove that
1loga m, 1logb m,1logc m are in A.P.

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Solution

a, b, c are in G.P.
b2 = ac Now taking logm on both the sides:logmb2 = logmac2logmb = logma + logmc2logbm = 1logam +1logcmThus, 1logam, 1logbm and 1logcm are in A.P.

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