If a,b,c are in G.P, then the equation ax2+2bx+c=0 and dx2+2ex+f=0 have a common root if da,eb,fc are in
A.P.
As given b2=ac⇒ax2+2bx+c=0 can be written as ax2+2√acx+c=0
⇒ (√ax+√c)2=0⇒x=−√ca
repeated root
This must be the common root by hypothesis.
So it must satisfy the equation dx2+2ex+f=0
⇒dca−2e√ca+f=0⇒da+fc=2ec√ca=2eb⇒da,eb,fc are in A.P