If a,b,c be three distinct positive numbers, then the value of the determinant ∣∣
∣∣abcbcacab∣∣
∣∣ is
A
negative
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B
positive
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C
zero
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D
not possible to determine
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Solution
The correct option is A negative ∣∣
∣∣abcbcacab∣∣
∣∣=−(a3+b3+c3−3abc) =−(a+b+c)(a2+b2+c2−ab−bc−ca)=−12(a+b+c)[(a−b)2+(b−c)2+(c−a)2] As all the numbers are positive, so clearly the determinant is negative.