There are three values of t for which the following system of equations has non-trivial solutions.

(a-t) x+by + cz=0

bx + (c - t) y +az=0

cx + ay + (b-t) z=0

We can express the product of the three values of t in the form of determainant as

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Solution

The correct option is A

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Similar questions

There are three values of t for which the following system of equations has non-trivial solutions.

(a-t) x+by + cz=0

bx + (c - t) y +az=0

cx + ay + (b-t) z=0

We can express the product of the three values of t in the form of determainant as

∣ ∣ ∣ ∣ \begin{matrix} a & b & c b & c & a c & a & b \end{matrix} ∣ ∣ ∣ ∣ =

Q. If

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∣ ∣ ∣ ∣ \begin{matrix} a & b & c b & c & a c & a & b \end{matrix} ∣ ∣ ∣ ∣

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$⎡ ⎢ ⎣ \begin{matrix} a & b & c b & c & a c & a & b \end{matrix} ⎤ ⎥ ⎦$ is

Q. If

⎡ ⎢ ⎣ \begin{matrix} a & b & c b & c & a c & a & b \end{matrix} ⎤ ⎥ ⎦

is a singular matrix and

a, b, c

are positive, then

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