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Question

If a,b,c be three distinct positive numbers, then the value of the determinant ∣∣ ∣∣abcbcacab∣∣ ∣∣ is

A
negative
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B
positive
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C
zero
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D
not possible to determine
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Solution

The correct option is A negative
∣ ∣abcbcacab∣ ∣=(a3+b3+c33abc)
=(a+b+c)(a2+b2+c2abbcca)=12(a+b+c)[(ab)2+(bc)2+(ca)2]
As all the numbers are positive, so clearly the determinant is negative.

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