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Combination with Restrictions

If a, b, c, d...

Question

If a,b,c,d,e are prime integers, then the number of divisors of $a b^{2} c^{2} d e$ excluding 1 as a factor, is

A

94

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B

72

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C

36

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D

71

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Solution

The correct option is D
71

The numbers of divisors = $(1 + 1) (2 + 1) (2 + 1) (1 + 1) (1 + 1) - 1$ = 71

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