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Question

If $$a, b, c, l, m$$ are in A.P., then the value of $$a - 4b + 6c - 4l + m$$ is


A
1
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B
2
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C
3
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D
0
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Solution

The correct option is D $$0$$
Since $$a, b, c ,l ,m$$ are in A.P, therefore,

$$a + m = 2c........(1)$$
$$b + l = 2c .........(2)$$

Now, consider

$$a-4b+6c-4l+m$$
$$=a+6c+m-4(b+l)$$
$$=a+m+6c-4(2c)$$       (using (2))
$$=2c+6c-4(2c)$$              (using (1))
$$=8c-8c$$
$$=0$$

Hence $$a-4b+6c-4l+m=0$$ 

Mathematics

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