If α, β, γ are the roots of the equation x3+4x+1=0,then (α+β)−1+(β+γ)−1+(γ+α)−1=
2
3
4
5
If α,β, γ are the roots of the equation
α+β+γ=0,αβ+βγ+γα=4,αβγ=−1
therefore(α+β)−1+(β+γ)−1+(γ+α)−1 =1−γ+1−α+1−β =−(αβ+βγ+γααβγ) =−(4−1)=4
If α,β,γ are roots equation x3+ax2+bx+c=0, then α−1+β−1+γ−1=