If a ball thrown vertically up attains a maximum height of $80 m,$ its initial speed is $(g = {10 m s}^{- 2})$ .

{40 m s}^{- 1}

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{20 m s}^{- 1}

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{50 m s}^{- 1}

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{10 m s}^{- 1}

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Solution

The correct option is A ${40 m s}^{- 1}$
Maximum height attained
$H = 80 m$
Initial speed $u = \sqrt{2 g H}$
The final speed will be zero because at the highest point it changes its direction.
$⟹ u = \sqrt{2 \times 10 \times 80} = 40 m / s$

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