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Question

If A=[1012], then A2=

A
2A3I
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B
3A2I
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C
3A+2I
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D
2A+3I
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Solution

The correct option is B 3A2I
A=[1012]

A2=[1012][1012]=[1034]
3A2I=3[1012]2[1001]=A2

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