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Question

If A=[234−348], B=[−147−3−25] and A+B=[1abc213], then find the value of a+b+c.

A
12
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B
21
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C
15
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D
5
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Solution

The correct option is A 12
Given, A=[234348], B=[147325] and A+B=[1abc213] ....(1)
Therefore,
A+B=[234348]+[147325]=[213+44+733428+5]=[17116213] .....(2)
By equating (1) and (2), we get
a+b+c=7+116=12

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