If A- i 0- 0 -i -B- 0 -1- 1 0 -C- 0 i- i 0 - where i - - -1 - then which one of the following is correct-

The correct option is D AB = C We have, AB=[ i amp; 0; 0 amp; i ][ 0 amp; 1; 1 amp; 0 ]=[ 0 amp; i; i amp; ...

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Evaluation of a Determinant

If A=[ i 0;...

Question

If $A = (\begin{matrix} i & 0 0 & - i \end{matrix}), B = (\begin{matrix} 0 & - 1 1 & 0 \end{matrix}), C = (\begin{matrix} 0 & i i & 0 \end{matrix})$ where $i = \sqrt{- 1}$ , then which one of the following is correct?

A B = - C

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A B = C

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A^{2} = B^{2} = C^{2} = I

, where

I

is the identity matrix

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B A \neq C

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Solution

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Similar questions

A = [\begin{matrix} i & 0 0 & - i \end{matrix}], B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}], C = [\begin{matrix} 0 & i i & 0 \end{matrix}]

A^{2} + B^{2} + C^{2} =

[\begin{matrix} i & 0 0 & - i \end{matrix}]

[\begin{matrix} 0 & - 1 1 & 0 \end{matrix}]

[\begin{matrix} 0 & i i & 0 \end{matrix}]

\neq

[\begin{matrix} 0 & i i & 0 \end{matrix}]

i^{2} = - 1

[\begin{matrix} 0 & i i & 0 \end{matrix}]

I + A + A^{2} + . . . . . A^{2010}

A = (\begin{matrix} i & 0 0 & i \end{matrix})

B = (\begin{matrix} 0 & - i - i & 0 \end{matrix})

i = \sqrt{- 1}

(A + B) (A - B)

A^{2} - B^{2}

A B = B A

a + i b = \frac{c + i}{c - i}

c

a^{2} + b^{2} = 1

\frac{b}{a} = \frac{2 c}{c^{2} - 1}

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