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Projectile from a Height

If a body is ...

Question

If a body is projected upward from certain height $h$ with initial velocity $u$ , then its speed at the ground level is.

u

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u + \sqrt{2 g h}

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\sqrt{u^{2} + 2 g h}

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u + 2 g h

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Solution

The correct option is C $\sqrt{u^{2} + 2 g h}$
correct option $(B)$

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\sqrt{u^{2} - 2 g h .}

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If v²=u²- 2gh & v=9, u=41, h =25, then g is equal to

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Column-I	Column-II
(a)	The speed of body at any time $t$ is	(p)	$\sqrt{\frac{2 g h}{u^{2}}}$
(b)	It will strike the ground after time $t$ equal to	(q)	$\sqrt{\frac{2 h}{g}}$
(c)	The path followed by the body is expressed as $y$ equal to	(r)	$- \frac{1}{2} g \frac{x^{2}}{u^{2}}$
(d)	The tangent of the angle $θ$ made by velocity vector striking the ground with horizontal is equal to	(s)	$\sqrt{u^{2} + g^{2} t^{2}}$

If a body is thrown up with an initial velocity, $u$ and covers a maximum height, $h$ , then $h$ is equal to $\frac{u^{2}}{2 g}$ .

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