If a body is thrown up with the velocity of $15 m / s$ , then maximum height attained by the body is $(g = 10 m / s^{2})$

11.25 m

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16.2 m

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24.5 m

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7.62 m

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Solution

The correct option is A $11.25 m$
$v^{2} = u^{2} + 2 a s$
$Substituting u = 15 m / s, v = 0 m / s, a = g = - 10 m / s^{2},$
$15^{2} = 2 \times 10 \times s$
$s = 225 / 20 = 11.25 m$

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