If a box of sweets is divided among 24 children, they will get 5 sweets each. How many would each get, if the number of children is reduced by 4?
6
As the number of children increases, the number of sweets for each decreases. It is an inverse proportion.
Let the required number of sweets be x.
In inverse proportion,
A1×B1 = A2×B2
⇒5×24=x×20
5x=2024
x=5×2420=6
So, each child gets 6 sweets.