If a-b x-2-1-4-3 x- then a- b-

The correct option is A (2,12) (a+bx)^ 2 = 1/a^2(1+ b/ax)^ 2 = 1/a^2[a + ( 2)/1!( b/a)x +........] Equating it to 1/4 3x + ......, we get a = 2, b = 12. ...

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Standard XI

Mathematics

Empty Set

If a+b x-2=1/...

Question

If $(a + b x)^{- 2}$ = $\frac{1}{4}$ - 3x + ......, then (a,b) =

(2,12)

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(-2,12)

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(2,-12)

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None of these

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Solution

The correct option is A
(2,12)

$(a + b x)^{- 2} = \frac{1}{a^{2}} (1 + \frac{b}{a} x)^{- 2} = \frac{1}{a^{2}} [a + \frac{(- 2)}{1!} (\frac{b}{a}) x + . . . . . . . .]$

Equating it to $\frac{1}{4}$ - 3x + ......, we get a = 2, b = 12.

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If (a+bx)−2 = 14 - 3x + ......, then (a,b) =

The correct option is A (2,12) (a+bx)−2=1a2(1+bax)−2=1a2[a+(−2)1!(ba)x+........] Equating it to 14 - 3x + ......, we get a = 2, b = 12.

If $(a + b x)^{- 2}$ = $\frac{1}{4}$ - 3x + ......, then (a,b) =

The correct option is A
(2,12)

$(a + b x)^{- 2} = \frac{1}{a^{2}} (1 + \frac{b}{a} x)^{- 2} = \frac{1}{a^{2}} [a + \frac{(- 2)}{1!} (\frac{b}{a}) x + . . . . . . . .]$

Equating it to $\frac{1}{4}$ - 3x + ......, we get a = 2, b = 12.