Question

If a coin is tossed twice,

Is the probability of getting two heads equal to the probability of getting no heads at all? Also find the probability of

i) Getting two heads

ii) Getting no heads

• A. No; ;
• B. No; ;
• C. Yes ;
• D. Yes ;

Answer 1

The correct option is C

Yes ;

Given,

Sample space = S { H H, H T, T H, T T}

$\Rightarrow$ Total number of outcomes = 4

Number of favourable outcomes = 1

Probability of an event, P(E) = $\frac{numberoffavourableoutcomes}{totalnumberofoutcomes}$

$\Rightarrow$ P(H H) = $\frac{1}{4}$

$\Rightarrow$ P(no heads at all) = P (T T) = $\frac{1}{4}$

Therefore, P(H H) = P(two heads) = P(no heads at all) = $\frac{1}{4}$