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Question

If a cos2(x+y)=b, then dydx equals

A
2
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B
-2
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C
1
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D
-1
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Solution

The correct option is D -1
Differentiating both sides w.r.t x
2acos(x+y).(sin(x+y))[1+dydx]=0
asin(2x+2y)[1+dydx]=0
x+y=nπ2 or dydx+1=0
In Both cases dydx=1


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