If a crop of wheat removes 20 kg of nitrogen per hectare of soil, what mass (in kg) of the fertilizer calcium nitrate would be required to replace the nitrogen in a 10 hectare field?
[N=14; O=16; Ca=40]

1171 kg

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2342 kg

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585.5 kg

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1395.45 kg

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Solution

The correct option is A 1171 kg
One hector consumes 20 kg of nitrogen. So total nitrogen consumption, $20 \times 10 = 200 k g$ .
Molecular formula of calcium nitrate is $C a (N O_{3})_{2}$
So,164 parts of calcium nitrate contains 28 parts of nitrogen.
So, 1 part of nitrogen is found in 164/28 parts of calcium nitrate.
So, 200 kg of nitrogen is found in, $(164 / 28 \times 200) = 1171.4 k g$ of calcium nitrate. So the correct option is A

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If a crop of wheat removes 20 kg of nitrogen per hectare of soil, what mass (in kg) of the fertilizer calcium nitrate would be required to replace the nitrogen in a 10 hectare field? [N=14; O=16; Ca=40]

If a crop of wheat removes 20 kg of nitrogen per hectare of soil, what mass (in kg) of the fertilizer calcium nitrate would be required to replace the nitrogen in a 10 hectare field?
[N=14; O=16; Ca=40]