If a current I given by I0 sin - t - -2 flows in an ac circuit across which an ac potential of E - E0 sin - t has been applied- then the power consumption P in the circuit will be

Phase angle ϕ = 90^∘, so power P = Vi cos ϕ = 0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Power Factor

If a current ...

Question

If a current I given by $I_{0} s i n (ω t - \frac{π}{2})$ flows in an ac circuit across which an ac potential of $E = E_{0} s i n ω t$ has been applied, then the power consumption P in the circuit will be

P = \frac{E_{0} I_{0}}{\sqrt{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P = \sqrt{2} E_{0} I_{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P = \frac{E_{0} I_{0}}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

I

I_{0} sin (ω t - π / 2)

E_{0} sin ω t

P

I

I = I_{0} sin (ω t - π / 2)

E = E_{0} sin ω t

P

I_{0} s i n (ω t - \frac{π}{2})

E = E_{0} s i n ω t

A C

V = 200 sin 100 t

I = 5 sin (100 t - \frac{π}{2})

i = 5 s i n (100 t - \frac{π}{2})

V = 200 s i n (100) v o l t .

Join BYJU'S Learning Program