Question

If a experiment starts with $1,000$ grams of Chloroform and uses $522.5$ grams, Calculate the moles of Chlorine left.

• A. 12
• B. 13
• C. 14
• D. 15

Answer 1

The correct option is A 12

Total mass of $CHC{l}_3$ is $=12.011+1.008+(3\times 35.453)=118.376$.

Now, the remaining mass of chloroform is $1000-522.5=477.5$.

Hence moles of chloroform left is $=\frac{477.5}{118.376}=4.03$ moles.

$1$ mole of chloroform contains $3$ moles of chlorine.

Hence, $4.03$ moles of chloroform will contain $4.03\times 3=12.09$ moles.