If a fcc arrangement of A and B atoms, where A atoms are at the corner of the unit cell and B atoms at the face centres, one of the A atom is missing from one corner in each unit cell. What is the simplest formula of compound?

A_{7} B_{24}

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A B_{2}

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A_{5} B_{22}

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A_{3} B_{7}

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Solution

The correct option is B $A_{7} B_{24}$
No. of atoms of A from corners of unit cell = $\frac{7}{8}$
No. of atoms of B from faces of unit cell $= 3$

Thus $A : B = \frac{7}{8} : 3$
$o r 7 : 24$
Thus the formula is $A_{7} B_{24}$

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If a fcc arrangement of A and B atoms, where A atoms are at the corner of the unit cell and B atoms at the face centres, one of the A atom is missing from one corner in each unit cell. What is the simplest formula of compound?

The correct option is B A7B24No. of atoms of A from corners of unit cell =78 No. of atoms of B from faces of unit cell =3 Thus A:B=78:3 or7:24Thus the formula isA7B24

The correct option is B $A_{7} B_{24}$
No. of atoms of A from corners of unit cell = $\frac{7}{8}$
No. of atoms of B from faces of unit cell $= 3$

Thus $A : B = \frac{7}{8} : 3$
$o r 7 : 24$
Thus the formula is $A_{7} B_{24}$