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Question

In an FCC arrangement of A and B atoms, where A atoms are at the corners of the unit cell, B atoms at the face centers, two atoms are missing from two corners in each unit cell, then the simplest formula of a compound is


A

AB6

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B

A2B3

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C

A7B24

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D

AB4

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Solution

The correct option is D

AB4


Since there are six atoms (A) in the corner of the unit cell, the contribution of atoms in 1 unit cell is 6/8 = 3/4. Since 3 face-centered atoms (B) contribute to one unit cell, the formula is A0.75B3

= A3B12

= AB4.


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