In CCP arrangement of A and B atoms, A atoms are at the corners of unit cell, while B atoms are at the face centre. In each unit cell two atoms are missing from the two corners. The simplest formula of the compound is

A_{3} B

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A B_{4}

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A_{7} B_{24}

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A_{6} B_{7}

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Solution

The correct option is B $A B_{4}$
No. of ‘A’ atoms per unit cell $= 6 \times \frac{1}{8} = 0.75$
No. of ‘B’ atoms per unit cell $= 6 \times \frac{1}{2} = 3$
Simple ratios of A : B is 0.75 : 3 or 1 : 4
$E F = A B_{4}$

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In CCP arrangement of A and B atoms, A atoms are at the corners of unit cell, while B atoms are at the face centre. In each unit cell two atoms are missing from the two corners. The simplest formula of the compound is

The correct option is B AB4No. of ‘A’ atoms per unit cell =6×18=0.75 No. of ‘B’ atoms per unit cell =6×12=3 Simple ratios of A : B is 0.75 : 3 or 1 : 4 EF=AB4

The correct option is B $A B_{4}$
No. of ‘A’ atoms per unit cell $= 6 \times \frac{1}{8} = 0.75$
No. of ‘B’ atoms per unit cell $= 6 \times \frac{1}{2} = 3$
Simple ratios of A : B is 0.75 : 3 or 1 : 4
$E F = A B_{4}$