If a force of 25 N acts on a body for 4 s and displaces it by 5 m, then the work done is joules, and the power is watts.

25.65

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150

No worries! We‘ve got your back. Try BYJU‘S free classes today!

125

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

31.25

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
C 125
D 31.25
Given: Force, $F = 25 N$
Displacement, $S = 5 m$
Time interval, $t = 4 s$
$Work done, W = Force \times Displacement$ $⟹ W = 25 \times 5 = 125 J$ .
Power = $\frac{Work}{Time taken}$ = $\frac{W}{t}$ $= \frac{125}{4} = 31.25 W$ .

Suggest Corrections

Similar questions

Q. If a force of 25 N acts on a body for 4 s and displaces it by 5 m, then the work done is joules, and the power is watts.

A position dependent force $F = 7 - 2 x + 3 x^{2}$ acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m. The work done in joules is

Q. A force

(3^i + 4^j) N

acts on a body and displaces it by

(3^i + 4^j)

meters. The work done by the force is
(Given that formula for work done is

W = \to F . \to s)

Q. If

\to F = 2^i + 3^j + 4^k

acts on a body and displaces it by

\to S = 3^i + 2^j + 5^k

, then the work done by the force is:

Join BYJU'S Learning Program

If a force of 25 N acts on a body for 4 s and displaces it by 5 m, then the work done is joules, and the power is watts.

The correct options are C 125 D 31.25Given: Force, F=25 N Displacement, S=5 m Time interval, t=4 s Work done,W=Force×Displacement⟹W=25×5=125 J. Power = WorkTime taken = Wt =1254=31.25 W.

The correct options are
C 125
D 31.25
Given: Force, $F = 25 N$
Displacement, $S = 5 m$
Time interval, $t = 4 s$
$Work done, W = Force \times Displacement$ $⟹ W = 25 \times 5 = 125 J$ .
Power = $\frac{Work}{Time taken}$ = $\frac{W}{t}$ $= \frac{125}{4} = 31.25 W$ .