Question

If a function f : R → R be defined by
$f\left(x\right)=\left\{\begin{array}{cc}3x-2,& x<0;\\ 1,& x=0;\\ 4x+1,& x>0.\end{array}\right.$
find: f(1), f(−1), f(0) and f(2).

Answer 1

f (1) = 4 × 1 + 1 = 5 [By using f (x) = 4x + 1, x > 0]
f ($-$ 1) = 3 × ($-$1) $-$ 2 [By using f (x) = 3x $-$ 2, x < 0]
= $-$ 3 $-$ 2 = $-$ 5
f (0) = 1 [By using f (x) = 1, x = 0]
f (2) = 4 × 2 + 1 [By using f (x) = 4x + 1, x > 0]
= 9
Hence,
f (1) = 5, f ($-$1) = $-$ 5, f (0) = 1 and f (2) = 9.