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Question

If a function f:RR be defined by f(x)=3x2,x<01,x=04x+1,x>0 Find f(1), f(1), f(0), f(2).

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Solution

f(1)=4(1)+1=4+1=5

f(1)=3(1)2=32=5

f(0)=1

f(2)=4(2)+1=8+1=9


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