Question

If a function is of form
$f\left(z\right)=\frac{g\left(z\right)}{h\left(z\right)}$, then
$f^{\prime }\left(z\right)=\frac{\frac{\left(h\right(z\left)\right)d\left(g\right(z\left)\right)}{dz}+g\left(z\right)\frac{d\left(h\right(z\left)\right)}{dz}}{\left(h\right(z){)}^2}$

• A. True
• B. False

Answer 1

The correct option is B False

For a function of the form
$f\left(z\right)=\frac{g\left(z\right)}{h\left(z\right)}$, $f^{\prime }\left(z\right)$ will be

$\frac{\frac{\left(h\right(z\left)\right)d\left(g\right(z\left)\right)}{dz}-g\left(z\right)\frac{d\left(h\right(z\left)\right)}{dz}}{\left(h\right(z){)}^2}$