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Question

If a gas at 10 atm and 300 K expands against a constant external pressure of 2 atm from a volume of 10 litres to 20 litres, the amount of work done is:
Given: 1 L.atm = 101.3 J

A
17 L.atm
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B
10 L.atm
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C
2026 J
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D
2026 J
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Solution

The correct option is C 2026 J
As the process is done at a constant external pressure, it is irreversible.
W=2010P.dV=20102dV
W=2[2010]
W=20 L.atm
As, 1 L.atm = 101.3 J
i.e W=20×101.3 J=2026 J

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