1
Question
If a gas at 5 atm and 373 K expands against a constant external pressure of 1 atm from a volume of 2 litres to 10 litres, the amount of work done is:
(Given: 1L.atm=101.3 J)
If a gas at 5 atm and 373 K expands against a constant external pressure of 1 atm from a volume of 2 litres to 10 litres, the amount of work done is:
(Given: 1L.atm=101.3 J)
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Solution
The correct option is D −810.4 J
As the process is done at a constant external pressure, it is irreversible.
W=−PΔV
⇒ W=−1 atm[10L−2L]
⇒ W=−8 L.atm
As, 1L.atm=101.3 J
i.e W=−8×101.3 J=−810.4 J
As the process is done at a constant external pressure, it is irreversible.
W=−PΔV
⇒ W=−1 atm[10L−2L]
⇒ W=−8 L.atm
As, 1L.atm=101.3 J
i.e W=−8×101.3 J=−810.4 J
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