If a given mass of gas occupies a volume of 10 cc at 1 atm pressure and temperature 100-C- What will be its volume at 4 atm- the temperature being the same-

We know, nbsp; For a given mass of an ideal gas at constant temperature, nbsp; PV = constant ⇒ P_1V_1 = P_2V_2 ⇒ 1 atm× 10 cc = 4 atm× V_2 ⇒ V_2 = 104 = ...

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Standard XIII

Physics

Gas laws from KTG

If a given ma...

Question

If a given mass of gas occupies a volume of $10 cc$ at $1 atm$ pressure and temperature $100^{\circ} C$ . What will be its volume at $4 atm$ , the temperature being the same?

104 cc

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2.5 cc

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400 cc

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10 cc

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Solution

The correct option is B $2.5 cc$
We know,
For a given mass of an ideal gas at constant temperature,
$P V =$ constant
$\Rightarrow P_{1} V_{1} = P_{2} V_{2}$
$\Rightarrow 1 atm \times 10 cc = 4 atm \times V_{2}$
$\Rightarrow V_{2} = \frac{10}{4} = 2.5 cc$

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If a given mass of gas occupies a volume of 10 cc at 1 atm pressure and temperature 100∘C. What will be its volume at 4 atm, the temperature being the same?

The correct option is B 2.5 ccWe know, For a given mass of an ideal gas at constant temperature, PV= constant ⇒P1V1=P2V2 ⇒1 atm×10 cc=4 atm×V2 ⇒V2=104=2.5 cc

If a given mass of gas occupies a volume of $10 cc$ at $1 atm$ pressure and temperature $100^{\circ} C$ . What will be its volume at $4 atm$ , the temperature being the same?

The correct option is B $2.5 cc$
We know,
For a given mass of an ideal gas at constant temperature,
$P V =$ constant
$\Rightarrow P_{1} V_{1} = P_{2} V_{2}$
$\Rightarrow 1 atm \times 10 cc = 4 atm \times V_{2}$
$\Rightarrow V_{2} = \frac{10}{4} = 2.5 cc$