If a heater of 100 Ω resistance draws a current of 5 A for an hour then find the energy consumed by the heater.
3600 KJ
9000 KJ
2500 KJ
1800 KJ
We have, I = 5, R = 100, t = 1 × 60 × 60 = 3600 seconds We know, H = I2RT H = 52 × 100 × 3600 = 9 × 106J H = 9000 KJ
If a heater of 100Ω resistance draws a current of 5A for an hour then find the energy consumed by the heater.