Question

# If $$a\in$$Z and the equation $$(x-a)(x-10)+1=0$$ has integral roots, then the values of $$a$$ are

A
10,8
B
12,10
C
12,8
D
18,10

Solution

## The correct option is C $$12, 8$$Since, $$a$$ and $$x$$ are integers.Therefore, $$(x-a)(x-10)+1=0$$$$\Rightarrow (x-a)(x-10)=-1$$$$\Rightarrow x-a=1$$ and $$x-10=-1$$or $$x-a=-1$$ and $$x-10=1$$$$\Rightarrow x=9$$ and $$a=8$$ or $$x=11$$ and $$a=12$$$$\Rightarrow a=8$$ or $$a=12$$.Quantitative Aptitude

Suggest Corrections

0

Similar questions
View More