If A is a skew symmetric matrix such that ATA=I, then A4n–1, (nϵN) is equal to
–AT
I
−I
AT
Given, A is skew symmetric matrix
So, AT=−A
Also ATA=I⇒−A2=I Taking square of both sides, we get A4=I
⇒A4n=I
⇒A4n−1=A4nA−1=IA−1=−A=AT
Matrix A is such that A2=2A−I, where I is the Identity matrix. Then for n≥2, An is equal to