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Question

If A={4n3n1:nϵN} and B={9(n1):nϵN}, then we have

A
AB
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B
AB=ϕ
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C
BA
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D
None of these
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Solution

The correct option is A AB
For n=1,4n3n1=431=0=9(11)ϵB
For n4,4n3n1=(1+3)n3n1
=(nC0+nC13+nC232+.....+nCn3n)=3n1
=nC232+.....+nCn3n=9(nC2+....+3n2)
=9{(nC2+.....+3n2+1)1}ϵB
AB.
Using roster method,
A={0,9,54,243,....}
and B={0,9,18,27,36,45,54,.....}
AB. (AB)

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