If A - - - i 0- 0 - i - then show that A 2 - - I

Given A=[ i amp; 0; 0 amp; i ] A^2=[ i amp; 0; 0 amp; i ][ i amp; 0; 0 amp; i ] =[ 1+0 amp; 0+0; ...

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Evaluation of a Determinant

If A = [ [ ...

Question

If $A = [\begin{matrix} i & 0 0 & - i \end{matrix}]$ then show that $A^{2} = - I$

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A = [\begin{matrix} i & 0 0 & - i \end{matrix}], B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}], C = [\begin{matrix} 0 & i i & 0 \end{matrix}]

A^{2} + B^{2} + C^{2} =

A = [\begin{matrix} i & 0 0 & - i \end{matrix}]

A^{2} = - I_{2}

\sqrt{\frac{1 + i}{1 - i}} = (a + i b)

(a^{2} + b^{2}) = 1

[\begin{matrix} i & 0 0 & - i \end{matrix}]

[\begin{matrix} 0 & - 1 1 & 0 \end{matrix}]

[\begin{matrix} 0 & i i & 0 \end{matrix}]

\neq

A = (\begin{matrix} i & 0 0 & i \end{matrix}), B = (\begin{matrix} - i & 0 0 & - i \end{matrix}), i = \sqrt{- 1}

Statement-I : (A + B) (A - B) = A^{2} - B^{2} Statement-II : A B = B A

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