If A-x - x - N - B-x - x - N and x is even - C-x - x - N and x is odd and D-x - x - N and x is prime then find A- D

Given A={ x:x∈ N } #160; D={ x:x∈ N and x is prime } #160; Thus, D⊂ A ∴ D∩ A=D ∴ D∩ A={ x:x∈ N and x is prime } # ...

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Intersection

If A=x : x ...

Question

If $A = {x : x \in N}, B = {x : x \in N a n d x i s e v e n}, C = {x : x \in N a n d x i s o d d}$ and $D = {x : x \in N a n d x i s p r i m e}$ then find
$A \cap D$

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Let A = { $x : x ϵ N$ }, B = { $x : x = 2 n, n ϵ N$ }, C = { $x : x = 2 n - 1, n ϵ N$ } and , D = {x: x is a prime natural number}. Find :

(i) $A \cap B$ (ii) $A \cap C$

(iii) $A \cap D$ (iv) $B \cap C$

(v) $B \cap D$ (vi) $C \cap D$

A = \{x : x \in N\}, B = \{x : x - 2 n, n \in N\}, C = \{x : x = 2 n - 1, n \in N\}

A \cap B

A \cap C

A \cap D

B \cap C

B \cap D

C \cap D

A = {x : x \in N},

$B = {x : x = 2 n, n \in N},$

$C = {x : x = 2 n - 1, n \in N} a n d$
$D = {x : x is a prime natural number}$ . Find.

(i) $(A \cap B)$

Let $A = {x : x \in N}, B = {x : x = 2 n, n \in N},$

$C = {x : x = 2 n - 1, n \in N} a n d$

$D = {x : x i s a p r i m e n a t u r a l n u m b e r} .$ Find.

(vi) $(C \cap D)$

Let $A = {x : x \in N}, B = {x : x = 2 n, n \in N},$

$C = {x : x = 2 n - 1, n \in N} a n d$

$D = {x : x i s a p r i m e n a t u r a l n u m b e r} .$ Find.

(v) $(B \cap D)$

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