If a linear equation has solutions (–3, 3), (-1,1), (1, -1) and (3, – 3), then find the X and Y intercepts of the graph of that equation.

Open in App

Solution

The points are all of the form (a, -a) [observation]

Therefore, the line has the equation x + y = 0.

It can be seen that this line passes through the origin.

Thus, the X intercept and the Y intercept are both equal to 0 because there is no constant term in the equation of line.

Suggest Corrections

Similar questions

If a linear equation has solutions (–3, 3), (-1,1), (1, -1) and (3, – 3), then find the X and Y intercepts of the graph of that equation.

(2, 3)

3 x - (a - 1) y = 2 a - 1 .

5 x + (1 - 2 a) y = 3 b,

b

Find value of a and b if y = 1 and x = 2 is solution of linear equation ax + by =3 and 3a – 2b = 1.

Show that the following system of linear equations has no solution:

$x + 2 y \leq 3, 3 x + 4 y \geq 12, x \geq 0, y \geq 1.$

Join BYJU'S Learning Program